
SpecialEd
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Math Problem...there is only one number!!!
#2403828  03/04/04 08:03 PM (13 years, 6 months ago) 


Assume that A = B
1. A*A = B * A
Distributive
2. A^2  B^2 = BA  B^2
Subtract B^2 from both sides
3. (A + B)(A  B) = B(A  B)
Factor
4. ((A + B)(A  B))/(A  B) = (B(A  B))/(A B)
Divide both sides by (A  B)
5. A + B = B
A = B so A + B = 2B
6. 2B = B
7. 2 = 1
Divide both sides by B
8. 1 = 0
Subtract one from both sides.
1 = 0, all numbers equal zero.
10 points for someone who tells me what is wrong here.
 "Plus one upvote +1..."
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Atomisk
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Re: Math Problem...there is only one number!!! [Re: SpecialEd]
#2403858  03/04/04 08:12 PM (13 years, 6 months ago) 


my cats breath smells like catfood.
 o housebuilder! thou art seen. thou shalt build no house again. all thy rafters are broken. thy ridgepole is shattered.

Letto
Load Universeinto Cannon. Aimat Brain. Fire.
Registered: 12/13/02
Posts: 2,321

Re: Math Problem...there is only one number!!! [Re: SpecialEd]
#2403886  03/04/04 08:21 PM (13 years, 6 months ago) 


The first step is actually the substitution property, but that doesn't really make a difference. I assume the error comes from when you divide by (AB). When you divide by variables (which cancels out the term), you lose a solution to the problem. This also happens when you divide 2B = B by B. The solution to this equation is only 0.
Also, when you have denominators, you have to make sure you don't get 0 on the bottom, which is exactly what you're doing when you divide by (AB), because AA = 0. Dividing by 0 is undefined. I'm not a mathematician, so somebody correct me if I'm wrong.

Ravus
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Re: Math Problem...there is only one number!!! [Re: Atomisk]
#2403892  03/04/04 08:23 PM (13 years, 6 months ago) 


My geometry teacher gave us this freshman year. I vaguely remember it, but after scanning it, since A = B, it'd be 1 minus 1, AKA 0. You can't divide by zero, otherwise all numbers would be equal to zero.
 So long as you are praised think only that you are not yet on your own path but on that of another.

Ravus
Not an EggshellWalker
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Re: Math Problem...there is only one number!!! [Re: Ravus]
#2403893  03/04/04 08:23 PM (13 years, 6 months ago) 


Ah, posted it before me. *shakes fist angrily*
 So long as you are praised think only that you are not yet on your own path but on that of another.

Letto
Load Universeinto Cannon. Aimat Brain. Fire.
Registered: 12/13/02
Posts: 2,321

Re: Math Problem...there is only one number!!! [Re: Ravus]
#2403898  03/04/04 08:24 PM (13 years, 6 months ago) 



SpecialEd
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Re: Math Problem...there is only one number!!! [Re: Ravus]
#2404178  03/04/04 09:42 PM (13 years, 6 months ago) 


Yeah, MMerletto gets the full ten points, but I will still give you five.
 "Plus one upvote +1..."
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trendal
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Re: Math Problem...there is only one number!!! [Re: SpecialEd]
#2404248  03/04/04 09:59 PM (13 years, 6 months ago) 


Without looking at the rest of the thread...
Your error is in step 4. You cannot divide by 0, and since A = B the term (A  B) equals 0, thus you cannot divide by (A  B).

Letto
Load Universeinto Cannon. Aimat Brain. Fire.
Registered: 12/13/02
Posts: 2,321

Re: Math Problem...there is only one number!!! [Re: SpecialEd]
#2404250  03/04/04 09:59 PM (13 years, 6 months ago) 


What are these points? Can I redeem them for stuffed animals or something?

trendal
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Re: Math Problem...there is only one number!!! [Re: trendal]
#2404254  03/04/04 10:00 PM (13 years, 6 months ago) 


Aw nuts. MMerletto beat me to it

SpecialEd
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Re: Math Problem...there is only one number!!! [Re: Letto]
#2404299  03/04/04 10:12 PM (13 years, 6 months ago) 


Quote:
What are these points? Can I redeem them for stuffed animals or something?
Next time you make a purchase, and they ask "Cash, Check, or Credit Card," say "Actually, I was going to use SpecialEd points, I will pay the difference in cash."
Trendal, I will give you five as well.
 "Plus one upvote +1..."
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tekramrepus
Registered: 02/20/02
Posts: 2,229

Re: Math Problem...there is only one number!!! [Re: SpecialEd]
#2405110  03/05/04 01:42 AM (13 years, 6 months ago) 


okay, without reading the replies, I'l have to say...
The first step is actually the substitution property, but that doesn't really make a difference. I assume the error comes from when you divide by (AB). When you divide by variables (which cancels out the term), you lose a solution to the problem. This also happens when you divide 2B = B by B. The solution to this equation is only 0.
Also, when you have denominators, you have to make sure you don't get 0 on the bottom, which is exactly what you're doing when you divide by (AB), because AA = 0. Dividing by 0 is undefined. I'm not a mathematician, so somebody correct me if I'm wrong.

tekramrepus
Registered: 02/20/02
Posts: 2,229

Re: Math Problem...there is only one number!!! [Re: tekramrepus]
#2405116  03/05/04 01:43 AM (13 years, 6 months ago) 


damnit, I wasnt the first one to get it

Shroomerious
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Re: Math Problem...there is only one number!!! [Re: SpecialEd]
#2405223  03/05/04 02:06 AM (13 years, 6 months ago) 


This is interesting if you look at it from another point of view. That it is another proof of the specific kind of maths, because if we were to divide by (AB) then one of it's basic principles would be violated and thus all numbers would equal zero which is unacceptable from this specific kind of maths. Of course the fact that we can not divide by 0 is one of the basic principles and doesn't need proof, but so to speak...


