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demiu5
humans, lol


Registered: 08/18/05
Posts: 43,948
Loc: the popcorn stadium
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fertilizer solution formula?
#7956151 - 01/30/08 03:37 PM (16 years, 2 days ago) |
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is there a basic formula for making fertilizer solutions? i've got a whole bunch of different chemicals i'm supposed to make 1000 gallon solutions with either 10 or 100ppm or said chemicals (this is all on paper, not real life).
however, i'm not understanding how the solubilities correlate with actually making a solution.
just so you know what i'm talking about, for example:
#1 use the previous info to make a 1000 gallon solution of 10ppm N using ammonium nitrate (both in grams/liters and lbs./gallons of water)
the solubility rates we found/used are: 21325 (gm/100 ml) and 2.8427 (ounce/gallon)...this is the "previous info"
*guessing where it say gm he is meaning gram
i've made fertilizer solutions for greenhouse crops before (using injector ratios and whatnot), but not like this
any help would be appreciated
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Asante
Mage


Registered: 02/06/02
Posts: 86,795
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Re: fertilizer solution formula? [Re: demiu5]
#7956237 - 01/30/08 04:00 PM (16 years, 2 days ago) |
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This is real easy.
How much weight percent of AN is nitrogen? How much weight is 10 ppm of a liter of water? If thats nitrogen, how much AN does that correspond to? Problem solved.
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raider
Stranger
Registered: 01/22/10
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Last seen: 14 years, 9 days
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Re: fertilizer solution formula? [Re: Asante]
#11878216 - 01/22/10 11:17 AM (14 years, 9 days ago) |
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Hi. Sorry to bump such an old topic, but I think I'm in the exact same class now that the original poster was in. 
Anyway, I think I'm getting the answer, but I just can't seem to figure out how the "previous info" that is mentioned actually works into the answer. I don't use any of the solubility rates that I had to look up before, is that correct? And do I need to adjust anything for the 1000 gallon solution requirement?
I'm just not sure because the wording on the worksheet says to use the previous information (we found the solubility rates in the first part) to help solve the ppm problems in the second part.
From calculating the first example in the original post and without using the "previous info" at all, I got 3.03^4 g/L. Does that sound right?
Sorry again to bump such an old topic. It's just driving me crazy how the worksheet states to use the previous info and I can't see how that would work into the problem in order to get the answer.
Thanks!
Edit: I included a copy of the first problem, so maybe this will help. The "information in Problem Set A-1" is the solubility of ammonium nitrate in g/100ml and ounce/gallon that the OP mentioned.
Quote:
Using the information in Problem Set A-1, make a 1,000 gallon solution of 10 ppm N using ammonium nitrate.
_______________ grams and _____________lbs of ammonium nitrate _______________ liters and ______________gallons of water
Make a 1,000 gallon solution of 100 ppm N using ammonium nitrate.
_______________ grams and _____________lbs of ammonium nitrate _______________ liters and ______________ gallons of water
Edited by raider (01/22/10 11:23 AM)
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Cyber
Ash



Registered: 06/14/04
Posts: 1,476
Loc: Dearborn Michigan
Last seen: 8 months, 18 days
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Re: fertilizer solution formula? [Re: raider]
#11882204 - 01/22/10 09:43 PM (14 years, 9 days ago) |
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Ok, First off it is a little more complicated than it sounds but Ill work through it for you
Ammonium Nitrate (NH4NO3)
According to the MSDS sheet it has a solubility of 150 g/100 ml (20 °C) and a molecular weight of 80.04g
This means that when you have dissolved 80.4g of Ammonium Nitrate in 1L of water you have a 1 mol
That breaks down as follows
N2 = 28.02 H = 4.04 O3 = 48.00
So at 1 mol you would have 28.02 ppm of nitrogen in each ml of water.
If you do this with each chemical you can add up the mols and determine the total PPM as well as the PPM of NPK
So, as an example if you create 1mol solutions of the following and add the listed ml of 1 mol solution to 1l of water you get the following
Potassium Nitrate -- KNO3 -- 5ml calcium nitrate – Ca(NO3)2·4H2O -- 5ml magnesium sulfate – MgSO4 -- 2ml Ammonium Nitrate – NH4NO3 -- 3ml Urea – (NH2)2CO --2ml Triple Super phosphate – Ca(H2PO4)2 --1ml
N 350.25ppm P 61.94ppm K 195.50ppm Mg 48.60ppm Ca 240.54ppm S 64.14ppm
Total PPM = 960.97
Add to that a micronutrient solution and you have a full hydroponic solution where you can control every aspect of it to the PPM.
Personally I worked it out years ago and created a spread sheet where I can put the ml per L and have it calculate it all for me. Makes it easy 
BTW, I dont know a single science teacher that would ask you to do it in gallons, so the initial question seems a bit odd. I think I have given you the information you are actually looking for, If I am wrong then let me know and ill see if I can do a better job of explaining it.
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M.Reynolds
Capt. of Serenity



Registered: 03/15/09
Posts: 482
Loc: Orbiting Deadwood
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Re: fertilizer solution formula? [Re: Cyber]
#11957883 - 02/03/10 09:23 PM (13 years, 11 months ago) |
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LOL, I remember having to do these. Are you taking a soil science class?
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