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Re: any math wizzes in the house? [Re: isaacein]
    #8945554 -

Let the equation circle jerk begin.

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Re: any math wizzes in the house? [Re: Irdamage]
    #8945563 -

Irdamage said:
Let the equation circle jerk begin.


e^(iπ) + 1 = 0. Thus God exists. Answer!


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Formula: 0

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Re: any math wizzes in the house? [Re: Irdamage]
    #8945564 -

ei*pi+1=0 :rockon:

Edit: Goddamnit someone beat me to it :lol:


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Bufotenine Yopo/Cebil Info | Guide to Hunting/Using Fly Agarics
Good Drug Books
PCPiHKAL|Rhodium

Edited by Entropymancer (09/17/08 07:59 PM)

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Re: any math wizzes in the house? [Re: Entropymancer]
    #8945569 -

I BEAT YOU HAHA


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Formula: 0

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Re: any math wizzes in the house? [Re: isaacein]
    #8945578 -

By 11 seconds :shakefist:


--------------------
Bufotenine Yopo/Cebil Info | Guide to Hunting/Using Fly Agarics
Good Drug Books
PCPiHKAL|Rhodium

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Re: any math wizzes in the house? [Re: isaacein]
    #8945581 -

Nicely done.  Yeah, although I'm pretty fast at straight-forward calculations and analytical logic, I still need to work on getting those flashes of creative insight that let you prove something.

And on the topic of ei*π, check out this paradox:

ei*π = -1
(ei*π)^2 = (-1)^2
e2*i*π = 1
ln(e2*i*π) = ln(1)

Hence, 2*i*pi = 0.


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We are all in the gutter, but some of us are looking at the stars.

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Re: any math wizzes in the house? [Re: Entropymancer]
    #8945586 -

Entropymancer said:
By 11 seconds :shakefist:


That must mean I'm 11 times better!

Now can you show that the average number of prime divisors (counted without multiplicity) of the numbers between 1 and n is asymptotic to the sum of the inverses of the primes in the same range?


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Formula: 0

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Re: any math wizzes in the house? [Re: deCypher]
    #8945589 -

:albundy:


--------------------
Bufotenine Yopo/Cebil Info | Guide to Hunting/Using Fly Agarics
Good Drug Books
PCPiHKAL|Rhodium

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Re: any math wizzes in the house? [Re: anyone420]
    #8945596 -

anyone420 said:
0 appples and one testicle


I feel for ya man... stephen has 3 testicles, maybe you could borrow one of his


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California Has Legalized Child Prostitution

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Re: any math wizzes in the house? [Re: Prisoner#1]
    #8945606 -

i have elephantitis in my single sacknut, so theres plenty of protein to go around


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for all y’all niggaz out there that be puffin shit
when the music go on, y’all listen to this alright

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Re: any math wizzes in the house? [Re: deCypher]
    #8945616 -

The Cypher said:
Nicely done.  Yeah, although I'm pretty fast at straight-forward calculations and analytical logic, I still need to work on getting those flashes of creative insight that let you prove something.

And on the topic of ei*π, check out this paradox:

ei*π = -1
(ei*π)^2 = (-1)^2
e2*i*π = 1
ln(e2*i*π) = ln(1)

Hence, 2*i*pi = 0.



Wikipedia said:
the logarithm function is a bijection from the set of positive real numbers to the set of all real numbers



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Formula: 0

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Re: any math wizzes in the house? [Re: isaacein]
    #8945618 -

"Calculus may be easy for you guys, but to me it looks like Newton was fucking with us.

"If you put a squiggly line before a number and dx after it you get something silly!"

"Ohh I love the silliness, we absolutely must make this universal mathematical law"

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Re: any math wizzes in the house? [Re: Irdamage]
    #8945622 -

Irdamage said:
"Calculus may be easy for you guys, but to me it looks like Newton was fucking with us.

"If you put a squiggly line before a number and dx after it you get something silly!"

"Ohh I love the silliness, we absolutely must make this universal mathematical law"


I have 2*2*2*2*2*2*2*2 posts! OMFG!!!!! :discodance:


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Formula: 0

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Re: any math wizzes in the house? [Re: isaacein]
    #8945630 -

isaacein said:
Wikipedia said:
the logarithm function is a bijection from the set of positive real numbers to the set of all real numbers




Well, you can technically extend the logarithm function into the complex domain, but then you have to maintain that:

ez = ez+2nπi to hold logical consistency.


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We are all in the gutter, but some of us are looking at the stars.

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Re: any math wizzes in the house? [Re: deCypher]
    #8945636 -

madness i tell you


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for all y’all niggaz out there that be puffin shit
when the music go on, y’all listen to this alright

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Re: any math wizzes in the house? [Re: anyone420]
    #8945638 -

Madness?  THIS... IS... SPARTAAAAA!



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We are all in the gutter, but some of us are looking at the stars.

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Re: any math wizzes in the house? [Re: Irdamage]
    #8945645 -

Its gonna degrade to a point where English is unrecognizable and all thats left is gobbildy gook between numbers.

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Re: any math wizzes in the house? [Re: isaacein]
    #8945651 -

How 'bout this one:

Let x be any positive integer constant.

Take x2 = x + x + x + ... } x times.

Then take the derivative of both sides with respect to x.

2x = d/dx (x + x + x + ... } x times)

2x = 1 + 1 + 1 + ... } x times.
2x = x

Since x is not equal to 0, we may divide by x on both sides and obtain:
2 = 1.


--------------------
We are all in the gutter, but some of us are looking at the stars.

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Re: any math wizzes in the house? [Re: Irdamage]
    #8945664 -

very good Cypher, your calc and algebra is strong. But it is no match for my Buddhist Palm attack! *flies through air* where are your precious physics now? bwahaha.

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Re: any math wizzes in the house? [Re: deCypher]
    #8945673 -

The Cypher said:
How 'bout this one:

Let x be any positive integer constant.

Take x2 = x + x + x + ... } x times.

Then take the derivative of both sides with respect to x.

2x = d/dx (x + x + x + ... } x times)

2x = 1 + 1 + 1 + ... } x times.
2x = x

Since x is not equal to 0, we may divide by x on both sides and obtain:
2 = 1.


You'd have to derive "} x times" as well!


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Formula: 0

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