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Stupid math question
    #11232685 -

real quick.. what is:

y2+5y ?



can it be broken down any?

:mushroom2:


Edited by subiedude (10/12/09 01:53 PM)

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Re: Stupid math question [Re: subiedude]
    #11232699 -

y=0 or y=-5

thats if y2+5y=0


--------------------

Song of the week, click Huey:



Song of the week list in journal.


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Re: Stupid math question [Re: subiedude]
    #11232701 -

it depends, what does it equal?

does it equal x or 5, or what?

there's way too many variables for the equation, what are the instructions?  are you trying to get an answer or a factor or what?

the only thing i can think of is y(y+5)

Edited by PMasterPoo (10/12/09 01:55 PM)

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Re: Stupid math question [Re: Tedwilto]
    #11232703 -

Tedwilto said:
y=0 or y=-5

thats if y2+5y=0


exactly.

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Re: Stupid math question [Re: Tedwilto]
    #11232705 -

the derivative is 2y+5. does that help?


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Re: Stupid math question [Re: subiedude]
    #11232708 -

That's already simplified.  if you factor it its y(y+5).  But I can't think of any answer to your question unless you're plugging in a value.


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drowse in prison and your waking will be but loss

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Re: Stupid math question [Re: PMasterPoo]
    #11232709 -

PMasterPoo said:
the only thing i can think of is y(y+5)


You got it, and from that, y=0 or -5.

Unless you're in complex variables, then there are several more answers in the imaginary plane.


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My name is Mud

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Re: Stupid math question [Re: DragonChaser]
    #11232720 -

i mean if you really wanted to you could put i^4 everywhere. but.. thats pointless


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Re: Stupid math question [Re: PMasterPoo]
    #11232721 -

solving rational equations

i gotta find the lcd with the denomonators being:

y2+5y

y+5

and..

y.


so what would the lcd be:blush:

Edited by subiedude (10/12/09 02:00 PM)

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Re: Stupid math question [Re: subiedude]
    #11232734 -

lowest common denominator?

I would leave it as y(y+5)

Thats about as far as you can go.


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Re: Stupid math question [Re: subiedude]
    #11232735 -

so lcd would be:

y(y+5), right?

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Re: Stupid math question [Re: subiedude]
    #11232737 -

ok thanks guys:thumbup:

i love the shroomery:grin::mushroom2:

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Re: Stupid math question [Re: subiedude]
    #11232742 -

ya shroomery > math tutor. lol

i do the same thing though.


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Re: Stupid math question [Re: subiedude]
    #11232774 -

subiedude said:
solving rational equations

i gotta find the lcd with the denomonators being:

y2+5y

y+5

and..

y.


so what would the lcd be:blush:


wait, you mean there's three different denominators?  that doesn't make sense...

then what's the numerator?

you must not be giving us all the information...

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Re: Stupid math question [Re: learningtofly]
    #11232809 -

learningtofly said:
i mean if you really wanted to you could put i^4 everywhere. but.. thats pointless



Not quite that simple.

Have you taken a class on complex variables?  I'm not talking about when they introduce the topic of sqrt(-1) in Algebra 2, I'm talking about a college course on the complex domain.


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My name is Mud

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Re: Stupid math question [Re: subiedude]
    #11232820 -

subiedude said:
solving rational equations

i gotta find the lcd with the denomonators being:

y2+5y

y+5

and..

y.


so what would the lcd be:blush:



if you have all those in the denominator, you would multiply each by each other to get the LCD.

so your LCD would be (y2+5y)(y+5)(y)


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Re: Stupid math question [Re: I AM SWIM]
    #11232855 -

Why doesn't OP just post the whole fucking problem?


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My name is Mud

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Re: Stupid math question [Re: DragonChaser]
    #11232920 -

3y+5 over y2+5y    +  y+4 over y+5  =  y+1 over y


solve the rational equation


Note: i dont know how to make fractions on here:shrug: so i just used the word "over" as the fraction bar

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Re: Stupid math question [Re: subiedude]
    #11232931 -

(mathy shit)/(more mathy shit) is how I normally do fractions.


--------------------
check out my music!
drowse in prison and your waking will be but loss

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Re: Stupid math question [Re: subiedude]
    #11233165 -

subiedude said:
3y+5 over y2+5y    +  y+4 over y+5  =  y+1 over y


solve the rational equation


Note: i dont know how to make fractions on here:shrug: so i just used the word "over" as the fraction bar



your LCD would be


(y^2+5y)(y+5)(y)

the '^ sign' implies that the y is raised to a power.


You multiply the LCD by each fraction and do the appropriate cancellation.

Eventually you will get

(3y+5)(y^2+5y) + (y+4)(y^3+5y) = (y+1)(y^3+10y^2+25y)


=



(3y^3+20y^2+25y) + (y^4+5y^2+4y^3+20y) = (y+1)(y^3+10y^2+25y)


then

y^4 + 7y^3 + 25y^2 + 45y = (y+1)(y^3+10y^2+25y)

then

(y^4 + 11y^3 +35y^2 +25y) = (y^4 + 7y^3 + 25y^2 + 45y)

so the statement is not true.

unless i did some thang wrong.


or you could move the right side to the left side and set it equal to zero.

or

(4y^3+10y^2) = 20

y = -10 - y^2  ALL over 4




I could be wrong.
how about you give it a try and see what you come up with.


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