
Grav
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algebra question
#2090507  11/10/03 09:40 PM (12 years, 11 months ago) 


ok this fuckin problem is driving me nuts...
can anyone show me step by step how to simplify this complex fraction?
........3
3 + 
........X
_________
........3
3  
........X
!??!?!
the book says the answer is: "x squared over (x  1) squared", but i cant see how to get there.
Edited by Grav (11/10/03 09:44 PM)

Letto
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Re: algebra question [Re: Grav]
#2090519  11/10/03 09:43 PM (12 years, 11 months ago) 


Are the fractions like [ (3 + 3) / x ] or [ (3 / x) + 3 ]???

Grav
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Re: algebra question [Re: Letto]
#2090522  11/10/03 09:45 PM (12 years, 11 months ago) 


i was havin trouble typing it out right... (3 / x) + 3

Grav
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Re: algebra question [Re: Grav]
#2090530  11/10/03 09:48 PM (12 years, 11 months ago) 


i get 3x^2 _________ 3x^2  6x  3
does that simplify to
x^2 _____ (x  1)^2
??

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Re: algebra question [Re: Grav]
#2090539  11/10/03 09:51 PM (12 years, 11 months ago) 


Sorry dude I tried but that is a difficult problem. Maybe I'll keep trying.

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Letto
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Re: algebra question [Re: Grav]
#2090563  11/10/03 10:06 PM (12 years, 11 months ago) 


I just got off the phone, so here is my solution. Just let me know if you don't understand any of my notation.
I made common denominators in the numerator and denominator to get:
[ (3x + 3) / x ] / [ (3x  3) / x ]
Then you multiply by the reciprocal of the denominator, so:
[ (3x + 3) / x ] * [ x / (3x  3) ] = (3x + 3) / (3x  3)
And that simplifies to (x + 1) / (x1)
I can't remember if I'm performing any illegal operations though, so let me know if you see any holes with my method.

Grav
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Re: algebra question [Re: Letto]
#2090639  11/10/03 10:34 PM (12 years, 11 months ago) 


hrmm... well for the common denominator for the first term wouldnt it have to be (x  1) ?
i figured it out though trying it your way ... it came out the same answer as it did my method but i noticed the 3 at the end of the denominator was supposed to be a +3 which let me factor the denominator into (x1)^2
sweet

Letto
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Re: algebra question [Re: Grav]
#2090656  11/10/03 10:43 PM (12 years, 11 months ago) 


If you just take the expression:
(3 / x) + (3 / 1)
The least common denominator will be x, so you have:
(3 / x) + (3x / x)
Then you simplify and get:
[ (3x + 3) / x ]
Am I missing something? I don't see where the (x  1) your talking about could be.

Grav
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Re: algebra question [Re: Letto]
#2092601  11/11/03 03:16 PM (12 years, 11 months ago) 


shit, my bad
the top fraction had a (x1) denominator, not x
what math level are you at, Merletto?
im starting computer science in school, unfortunately i dont know jack shit with my math yet

Letto
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Re: algebra question [Re: Grav]
#2092620  11/11/03 03:20 PM (12 years, 11 months ago) 


Calc 1, but I think I know earlier maths pretty well (780 on SAT math section, 760 on SAT2 for math). In fact, I have math class in 15 minutes =(

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Re: algebra question [Re: Grav]
#2093741  11/11/03 08:43 PM (12 years, 11 months ago) 


Please rewrite your problem again now that your know how to write it!

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Letto
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Re: algebra question [Re: Its Pat]
#2093804  11/11/03 09:01 PM (12 years, 11 months ago) 


I think he means it's:
[ 3 + (3 / {x  1}) ] / [ 3  (3 / x) ]

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Re: algebra question [Re: Grav]
#2095682  11/12/03 05:56 AM (12 years, 11 months ago) 


That wasn't easy....:
Last step:

