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Invisibleblacksabbathrulz
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Registered: 05/22/02
Posts: 2,511
physics help needed on a problem
    #3716623 - 02/02/05 01:00 AM (12 years, 6 months ago)

Hi,
I am currently confused about how to do a physics problem. It is pretty straight forward I am sure, but I cannot figure it out:

A certain projectile is launched with an initial speed v0. At its highest point its speed is v0/7. What was the launch angle?

any help would be greatly appreciated.


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Invisiblephalloidin

Registered: 07/03/04
Posts: 865
Re: physics help needed on a problem [Re: blacksabbathrulz]
    #3716886 - 02/02/05 01:50 AM (12 years, 6 months ago)

hmm, is there anymore info. I don't see how you can determine the launch angle based on that alone. Is there any information about distance traveled, height reached, time?


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Invisibleblacksabbathrulz
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Registered: 05/22/02
Posts: 2,511
Re: physics help needed on a problem [Re: phalloidin]
    #3717491 - 02/02/05 04:59 AM (12 years, 6 months ago)

Quote:

MrTryptastic said:
hmm, is there anymore info.  I don't see how you can determine the launch angle based on that alone.  Is there any information about distance traveled, height reached, time?




No, thats the question in its entirety  :frown:


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Offlinephi1618
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Registered: 02/14/04
Posts: 4,102
Last seen: 7 years, 3 months
Re: physics help needed on a problem [Re: blacksabbathrulz]
    #3717653 - 02/02/05 05:51 AM (12 years, 6 months ago)

Assuming no friction, it's a conservation of energy problem.

When it's launched, it has some upward momentum - total momemtum * umm.. sin or cos of the angle. Convert this momentum to energy - it should be a multiple of the projectiles mass. Convert this energy to a height.

E = mv^2 = mgh (g=accelation of gravity), or somesuch.


Edit:
sorry, this is totally wrong, i misread the problem.

At it's highest point, all the momentum is the horizontal component; the vertical compnonent is gone.

So, when it's launched, the vertical component of it's momentum is seven times the horizontal. So, tan(angle) = 7.


Edit: wrong again, only closer
total velocity (not vertical component) = 7 times horizontal component.

So, cos(angle) = 1/7.


Edited by phi1618 (02/02/05 05:57 AM)


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Offlinephi1618
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Registered: 02/14/04
Posts: 4,102
Last seen: 7 years, 3 months
Re: physics help needed on a problem [Re: blacksabbathrulz]
    #3717683 - 02/02/05 05:59 AM (12 years, 6 months ago)

Hey man, I coulda swore i won a contest you sponsored where I figgured out what a picture of a grain of starch was. I can't find any record of it, though, and it coulda been someone else entirely. I'm just confused.


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Invisiblephalloidin

Registered: 07/03/04
Posts: 865
Re: physics help needed on a problem [Re: phi1618]
    #3717983 - 02/02/05 07:56 AM (12 years, 6 months ago)

ahh, that makes sense now. :thumbup:


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