PHP simple login

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elbisivni

Registered: 10/01/06
Posts: 2,839

PHP simple login

#7003449 - 06/03/07 02:05 PM (19 years, 2 months ago)

Trying to figure out a simple one for access to only one user, but am trying to take a somewhat secure route. With the code below I'm getting this error:
Code:

Warning: session_start() [function.session-start]: Cannot send session cookie - headers already sent by (output started at -url-/index.php:12) in -url-/index.php on line 40

I've tried 4 or 5 different methods now but to no avail. If someone can peruse my code and point out any problems are point me in a better direction I'd really appreciate it.

BTW line 40 is "session_start();"

index.php
Code:

	<?
		session_start();

		if (isset($_SESSION['username'])){
			$login=true;
		} else {
			$login=false;
		}

		if($login==false){
			print("<table border=\"0\">
			<tr><td>Username:</td><td>Password:<;/td><td></td></tr>
			<tr><td><form name=\"login\" method=\"post\" action=\"user.php\"><input name=\"username\" type=\"text\" id=\"username\"></td>&lt;td><input name=\"password\" type=\"password\" id=\"password\"></td>&lt;td><input name=\"f\" type=\"hidden\" value=\"login\" /><input type=\"submit\" name=\"submit\" value=\"Log In\"></form></td></tr>
			</table>");
		}
		if($login==true){
			print("<a href=\"logout.php\">Log Out</a>");
		}

		include("connection.php");

		...

user.php
(functions as login and logout based on hidden param submitted by form)
Code:

<?
	include("connection.php");
	$function=$_POST['f'];

	if($function=="login"){
		if(isset($submit)){
			$result=mysql_query("SELECT * FROM users WHERE username='$username' AND password='$password'");
			$isAuth=false;
			while($row=mysql_fetch_array($result)){
				if($row['username']==$username){
					$isAuth = true;
					session_start();
					session_register('username');
				}
			}
			mysql_close($connection);
			if($isAuth){
				print "Login successful.<br><a href=\"index.php\">Return to Index</a>";
			} else {
				print "Login unsuccessful.";
			}
		}
	}

	if($function=="logout"){
		session_start();
		if(isset($_SESSION['phplogin'])){
			unset($_SESSION['phplogin']);
		}
		header('Location: index.php');
		exit();
	}
?>

--------------------
From dust you are made and to dust you shall return.

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elbisivni

Registered: 10/01/06
Posts: 2,839

Re: PHP simple login

[Re: elbisivni]
#7003697 - 06/03/07 03:19 PM (19 years, 2 months ago)

I fixed the session_start(); error by placing it at the very top of the page. I worked on the scripts some more but still no beans. I submit the form to login on index.php, it moves to user.php, but always results in a failure.

index.php
Code:

<?
	session_start();
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" />
<title>Music Index</title>
</head>
<body>
	<?
		include("connection.php");

		if(!session_is_registered('member_id')){
			$login=false;
		} else {
			$login=true;
		}
		
		if($login==false){
			print("<table border=\"0\">
			<tr><td>Username:</td><td>Password:<;/td><td></td></tr>
			<tr><td><form name=\"login\" method=\"post\" action=\"user.php\"><input name=\"username\" type=\"text\" id=\"username\"></td>&lt;td><input name=\"password\" type=\"password\" id=\"password\"></td>&lt;td><input name=\"f\" type=\"hidden\" value=\"login\" /><input type=\"submit\" name=\"submit\" value=\"Log In\"></form></td></tr>
			</table>");
		}
		if($login==true){
			print("<a href=\"logout.php\">Log Out</a>");
		}
		...

user.php
Code:

<?
	$function=$_POST['f'];
	
	if($function=="login"){
		session_start();
		include("connection.php");
		if(isset($_POST['submit'])){
			$username=strip_tags($_POST['username']);
			$password=sha1(strip_tags($_POST['password']));
			$query=sprintf("SELECT id FROM users WHERE username='%s' AND password='%s' LIMIT 1;",mysql_real_escape_string($username),mysql_real_escape_string($password));
			$result=mysql_query($query);
			if(1!=mysql_num_rows($result)){
				print("failure.");
			} else {
				$row=mysql_fetch_assoc($result);
				$_SESSION['member_id']=$row['id'];
				print("success.");
			}
		}
	}

	if($function=="logout"){
		session_start();
		if(true===session_unregister('member_id')){
			print("logged out.");
		} else {
		 	unset($_SESSION['member_id']);
		 	sleep(3);
			print("logged out.");
		}		
	}
?>

--------------------
From dust you are made and to dust you shall return.

Edited by elbisivni (06/03/07 03:34 PM)

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elbisivni

Registered: 10/01/06
Posts: 2,839

Re: PHP simple login

[Re: elbisivni]
#7004035 - 06/03/07 04:40 PM (19 years, 2 months ago)

never mind I figured it out, thanks for all of the help people :firecum:

--------------------
From dust you are made and to dust you shall return.

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delta9
Active Ingredient

Registered: 10/28/04
Posts: 5,390
Loc: California
Last seen: 15 years, 9 months

Re: PHP simple login

[Re: elbisivni]
#7006221 - 06/04/07 01:39 AM (19 years, 2 months ago)

PHP Session Reference

Sorry, was busy all weekend. :smile:

--------------------
delta⁹

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Seuss
Error: divide byzero

Registered: 04/27/01
Posts: 23,480
Loc: Caribbean
Last seen: 1 year, 5 months

Re: PHP simple login

[Re: delta9]
#7006407 - 06/04/07 04:40 AM (19 years, 2 months ago)

> Warning: session_start() [function.session-start]: Cannot send session cookie - headers already sent by (output started at -url-/index.php:12) in -url-/index.php on line 40

This happens when you try to set a cookie after non-header data has been sent. With non-buffered output, a single new line before the first php tag can cause the problem. I know you already figured it out, but helping others in the future.

--------------------
Just another spore in the wind.

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