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Re: .999...(repeating) = 1 [Re: sleepy]
    #6340308 -

sleepy said:
"Surely if 9x = 9, then x = 1. But since x also equals .9999999... we get that .9999999... = 1. The algebra is impeccable."

thats his entire proof (from the original site). please do whatever you have to to understand that proof, because i don't.

he proved that .999999...=1 because .999999....=1?

thats not proof thats saying it is because it is



No, you are grossly oversimplifying his proof.

Allow x to be equal to 0.999999[repeating].

x = 0.999999[repeating]

Multiply the equation by 10.

x times 10 = 10x
0.999999[repeating] times 10 = 9.999999[repeating]

We then get 10x = 9.999999[repeating]

take x from both sides (remember, we started with x = 0.999999[repeating])

10x - x = 9x
9.999999[repeating] - x = 9.999999[repeating] - 0.999999[repeating] = 9.0

We now have 9x = 9.0

devide both sides by 9 and we get x = 1

if x = 0.999999[repeating] and x = 1 then 1 = 0.999999[repeating]

I'm not a mathematician, but that makes perfect logical sense to me.

If you disagree, which stage of the calculation do you take issue with?

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Re: .999...(repeating) = 1 [Re: sleepy]
    #6340368 -

> the problem is that .99999999999 is infinitely not 1

I have no idea what "infinitely not 1" means. 0.999... (repeating) is exactly equal to 1 just like 0.3333... (repeating) is exactly equal to 1/3. What is so difficult about this concept?

> and .9999x where x is whatever place you go to (tenths, hundredths, thousandths), it will be 9/x bigger than the last one

Great, you are on the correct path. Now take the limit as you approach infinity and tell me what your answer is. If you do it correctly, your answer is *gasp* 1. (exactly)

> .9999 multiplied by infinity equals 1

No, it equals infinity just as .9999 multiplied by 0 equals 0.

> infinity goes on forever by definition

"Infinity is the state of being greater than any finite (real or natural) number, however large." (source: wiki) It is also wise to think of it in terms of something which is equal to the sum of it's parts. (source: seuss)

It is a mistake to confuse the philosophical view of infinity with the mathematical view. They are not the same.

> because the math can be off a little bit.

Really? Are you sure we didn't switch to philosophy rather than math?

> its true that .99999infinity = 1, perhaps

If by ".99999infinity" you mean 0.999... (repeating), then there is no perhaps about it. It is a fact just like 2=2 and 10/10=1. If you mean .9999 times infinity equals 1, then you are incorrect, as the correct answer is infinity.


--------------------
Just another spore in the wind.

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Re: .999...(repeating) = 1 [Re: Seuss]
    #6340490 -

Ok, I thought about this a bit more... let me see if this helps:

Quote:
picture a circle graph with .999 filled in

now

fill in .9999
now fill in .999999

each time you are adding 1 more step

.9
.99
.999



Look at 1/x ratios:

1/1 = 1
1/2 = 0.5
1/50 = 0.02
1/1234 = 0.0008 (aprox)
1/123456789 = .000000008 (aprox)

Do you see the trend?  As the value of x gets large, the value of the ratio gets small.  As we continue this trend, making x larger and larger, the value of the ratio approaches 0.  If we were to make x as large as possible, the number next to infinity, then the value of the ratio would be as small as possible, the number next to 0.  If we were actually able to make x equal infinity, then the ratio would actually equal 0.  This is known as a limit and is written as:



I won't go into the proof of limits, but if you care you can look it up.  It is called the epsilon-delta proof and is one of the foundations of calculus.

Now lets go back to your circle concept.  Assume the area of your circle is 1 (exact).  Now subtract off a little bit from the area,  say 1/x.  The formula for the area of the circle is now:



Now, what happens as you take the limit of the area as x approaches infinity?



We already showed that the limit of 1/x as x approaches infinity is 0, and 1 is not dependent upon x, therefore 1 doesn't change regardless of what x does, thus the answer to the above equation reduces to 1-0 which is 1 (exactly).

I hope this one makes sense, 'cause I am running out of ways to explain this.  :smile:

Edit:

Ok... one last attempt:

If you look up convergence of infinite geometric series, you will find the following (for |r|<1):



We can rewrite 0.999... (repeating) as:



Anything to the 0 power is 0.  Anything to the 1 power is itself.  So one can think of the above as:



The value of r is less than one (it is 1/10), so we can apply the rule of convergence of infinite geometric series, reducing the series to:



I will leave the algebra to the reader, but a good guess as to the correct answer is 1.  :wink:

Edited by Seuss (12/06/06 01:30 PM)

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Re: .999...(repeating) = 1 [Re: Seuss]
    #6341628 -

Decimals are an approximation, right?

You give a fraction, that is an exact value.

I like the analogy:

1/3 + 1/3 + 1/3 = 1

same as

.333- + .333- + .333- = 1

.999 repeating is an approximation of 1, not the exact value of it.

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Re: .999...(repeating) = 1 [Re: angryshroom]
    #6341776 -

If 0.333[repeating] is simply the nearest decimal approximation of 1/3, then surely 0.999[repeating] can't be the nearest decimal approximation of 1/1, as 0.999[repeating] is three times further away from 1/1 as 0.333[repeating] is from 1/3?


If the nearest decimal expressible value to 1/3 is 0.333[repeating], and we multiply it by three, then the "difference" between 0.333[repeating] and 1/3 is three times greater between 0.999[repeating] and 1/1.

How can you acount for the "difference" being bigger between 0.999[repeating] and 1, than between 0.333[repeating] and 1/3 ?

Curse you, base 10!

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Re: .999...(repeating) = 1 [Re: OJK]
    #6341961 -

http://en.wikipedia.org/wiki/0.999...

There you go, they have about 10 proofs of it, some involving real analysis which if you are questioning the reality of this statement Id recommend ignoring and focusing on the easier proofs. Honestly though, there are the proofs; if you want to argue specific steps in the proof point out the specific steps you find illogical, otherwise I don't see any reason this thread should continue.

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Re: .999...(repeating) = 1 [Re: OJK]
    #6342293 -

I dont think I agree with you :smile:

Thinking in terms of the real world.... .99999999 to infinity would be 1. Numerically, its hard to grasp, but, physically, its equal to 1. I donno, it makes sense in my brain but, hard to explain in words.

Not to mention we dont have any devices that could weigh the difference betweeen .9999 infinity and 1.

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Re: .999...(repeating) = 1 [Re: angryshroom]
    #6342336 -

> Decimals are an approximation, right?

Wrong. Is 0.5 an approximation of 1/2? No, it is exactly 1/2. Is 0.999... an approximation of 1? Nope, it is exactly 1. Think of it as two different ways of writing the exact same value.

> Not to mention we dont have any devices that could weigh the difference betweeen .9999 infinity and 1.

That is because there is no difference between the values 0.9999... and 1. If you subtract the two, you get 0 as the result.


> If the nearest decimal expressible value to 1/3 is 0.333[repeating]

False. 0.3333... is exactly 1/3, it is not the nearest decimal. The value of these two symbols is exactly the same. If you multipy 0.3333.... by 3, you get the exact value of 1, not 1-epsilon. If you multiply 0.9999... by 1, you get the exact value of 1, not 1-epsilon. The difference isn't bigger, it is zero in both cases.

> How can you acount for the "difference" being bigger between 0.999[repeating] and 1, than between 0.333[repeating] and 1/3 ?

Through a general lack of understanding of the concept of infinity and limits.


--------------------
Just another spore in the wind.

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Re: .999...(repeating) = 1 [Re: Seuss]
    #6343409 -

My post was a reply to angryshroom's definition of 0.999[repeating] as an approximation of 1, not an attempt to define 0.999[repeating] as an approximation of one.

I was trying to point out inconsistencies in viewing decimals as approximations of fractions, not argue they were approximations of fractions.

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Re: .999...(repeating) = 1 [Re: OJK]
    #6343507 -

Quote:
I was trying to point out inconsistencies in viewing decimals as approximations of fractions, not argue they were approximations of fractions.



I kind of suspected that after I made the reply... but I went ahead and left it as it, for the explanation.


--------------------
Just another spore in the wind.

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Re: .999...(repeating) = 1 [Re: Seuss]
    #6344630 -

I guess Im trying to say that when you want an exact answer, you leave in fractional form... therefor the the decimal notation is considered an approximation.

Say you have the value: "root(2)/2". That is an exact value, instead of writing in decimal notation, (0.70710678118654752440084436210485) where it will be rounded up eventually.

I agree that .999(repeating to infinity) = 1.


Edited by angryshroom (12/07/06 01:35 PM)

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Re: .999...(repeating) = 1 [Re: angryshroom]
    #6344690 -

CHANGING MY ANSWER


.999999...can never be a whole number no matter how hard you try. 1 is 1.00000 not .999999



there is no possible way you caould make those two equal.


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[quote]Gumby said:
And if you are going to waste peoples time with your stupid questions, at least try to have grammar skills higher then that of a 7th grader.

READ DAMNIT! [/quote]

Edited by nobhdy (12/07/06 02:10 PM)

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Re: .999...(repeating) = 1 [Re: nobhdy]
    #6344720 -

nobhdy said:
MATHS IS WRONG :crankey:



:sun:

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Re: .999...(repeating) = 1 [Re: OJK]
    #6344724 -

what?

i did not.

trippy avy btw....


--------------------
[quote]Gumby said:
And if you are going to waste peoples time with your stupid questions, at least try to have grammar skills higher then that of a 7th grader.

READ DAMNIT! [/quote]

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Re: .999...(repeating) = 1 [Re: nobhdy]
    #6344750 -

I didn't read this whole thread..

but .9999 repeating is an aproximation!

Just like .3333 repeating


If you were required on a test to give an exact answer, 1/3 would be correct, where .3333 repeating is not exactly the same. It's an approximation.

.9999 repeating is an aproximation of the whole number 1

so the correct way for writing it is 1

.99999 repeating is 1.

.999999 repeating is 1

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Re: .999...(repeating) = 1 [Re: Boom]
    #6344764 -

but aproximation IS NOT a whole number by any standard.

.99999 cannot and will never = 1. it is not physically possible.


and why are you so happy?


--------------------
[quote]Gumby said:
And if you are going to waste peoples time with your stupid questions, at least try to have grammar skills higher then that of a 7th grader.

READ DAMNIT! [/quote]

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Re: .999...(repeating) = 1 [Re: nobhdy]
    #6344775 -

the number .99999 repeating isn't physically possible

it's abstract, it's the number 1 !!



and I just haven't changed my mood in a while

It should say "Drowning in a sea of deadlines and exams"

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Re: .999...(repeating) = 1 [Re: Boom]
    #6344791 -

hmmm.

same.

prozac and coffe, anyone?

exactly. it IS abstract, but its NOT one.


--------------------
[quote]Gumby said:
And if you are going to waste peoples time with your stupid questions, at least try to have grammar skills higher then that of a 7th grader.

READ DAMNIT! [/quote]

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Re: .999...(repeating) = 1 [Re: nobhdy]
    #6344809 -

Yeah. It definitly is 1

Ok I read the whole thread. And now I'm more convinced. You're wrong.

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Re: .999...(repeating) = 1 [Re: Boom]
    #6344894 -

.999.... = 1 is correct 99.999....% of the time.

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