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PHY 101 Projectile motion homework
    #21507337 -

A back us thrown rock is thrown upward with 20 m/s at 50 degrees with respect to the horizontal. As it rises, neglecting air drag, what will be its horizontal and vertical component?

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Re: PHY 101 Projectile motion homework [Re: Mr. Penguin]
    #21507344 -

Well what do you know about it? I'm not going to do it for you

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Re: PHY 101 Projectile motion homework [Re: Mr. Penguin] * 1
    #21507347 -

Horizontal 20cos50
Vertical 20sin50

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Re: PHY 101 Projectile motion homework [Re: Uzziel]
    #21507356 -

yes, it will land right through the window of your prof's li\ving room


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EVERYTHING EVENTUALLY BECOMES A DESERT


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Re: PHY 101 Projectile motion homework [Re: I_was_the_walrus]
    #21507398 -

I_was_the_walrus said:
Horizontal 20cos50
Vertical 20sin50



Yep this is it


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Re: PHY 101 Projectile motion homework [Re: Salomon]
    #21507410 -

Ya i just don't want the answer i need to understand it. So the horizontal v= Vo COS Theta.

20 COS 50= 12.86 for my horizontal component?

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Re: PHY 101 Projectile motion homework [Re: Mr. Penguin]
    #21507413 -

oh sweet thanks blackhawk

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Re: PHY 101 Projectile motion homework [Re: Mr. Penguin]
    #21507421 -



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Re: PHY 101 Projectile motion homework [Re: Mr. Penguin]
    #21507423 -

http://www.mathsisfun.com/algebra/sohcahtoa.html

same thing just distances not vectors

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Re: PHY 101 Projectile motion homework [Re: Mr. Penguin]
    #21507433 -

SohCahToa

Some old hippie caught another hippie tripping on acid.

You have the hypotenuse - 20 m/s. To find the horizontal component (adjacent to angle) C=A/H

Adjacent (horizontal) = HCos(theta)= 20cos(50)

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Re: PHY 101 Projectile motion homework [Re: I_was_the_walrus]
    #21507451 -

Dude I'm totally going to pass this test now:dancer:
#2 A projectile falls beneath the straight line path it follows if there were no gravity. How many meters does it fall below this line if it has need traveling for 1 sec and for 2 sec? Assume acceleration die to gravity is 9.8m/sec>2

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Re: PHY 101 Projectile motion homework [Re: Mr. Penguin]
    #21507462 -

Distance = (Initial Velocity * time) + 1/2 (acceleration * time^2)

Do you understand what to do? Initial velocity is equal to 0 if the projectile is simply dropped.

Edited by KingKnowledge (04/05/15 07:13 PM)

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Re: PHY 101 Projectile motion homework [Re: KingKnowledge]
    #21507478 -

LOL I don't even understand the question. What dey want?


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Re: PHY 101 Projectile motion homework [Re: blackhawk]
    #21507486 -

blackhawk said:
LOL I don't even understand the question. What dey want?



He didn't word it correctly :lol: but I'm assuming he's asking how far a projectile drops in the y-direction from rest under the sole force of gravity after 1 second and 2 seconds.

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Re: PHY 101 Projectile motion homework [Re: Mr. Penguin]
    #21507490 -

Mr. Penguin said:
A back us thrown rock is thrown upward with 20 m/s at 50 degrees with respect to the horizontal. As it rises, neglecting air drag, what will be its horizontal and vertical component?



Go to a baseball game and figure out a pop fly Nuffsaid.


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:kingcrankey: Please report me to a Mod for hurting your punk ass hippie feelings :flipthebird: And all time Champion thread killer.:thatsayes:

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Re: PHY 101 Projectile motion homework [Re: Salomon]
    #21507497 -

Salomon said:
yes, it will land right through the window of your prof's li\ving room



Seriously laughed out loud.


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Re: PHY 101 Projectile motion homework [Re: r00tuuu123]
    #21507503 -

A projectile falls beneath the straight line path it follows if there were no gravity. How many meters down it fall below this line if it has been traveling for 1 sec and for 2 sec? Assume acceleration die to gravity is 9.8 m/sec^2. That's word for word. My prof is indian and i can't understand anything he says

Edited by Mr. Penguin (04/05/15 07:23 PM)

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Re: PHY 101 Projectile motion homework [Re: Salomon]
    #21507516 -

Salomon said:
yes, it will land right through the window of your prof's li\ving room



That's funny as hell I'm still laughin. :raisemyglass:


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:kingcrankey: Please report me to a Mod for hurting your punk ass hippie feelings :flipthebird: And all time Champion thread killer.:thatsayes:

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Re: PHY 101 Projectile motion homework [Re: Mr. Penguin]
    #21507522 -

Yeah I'm starting to get it. Thought this was a continuation of the first problem like wtf? lol

Then yeah it's this
Distance = (Initial Velocity * time) + 1/2 (acceleration * time^2)

Initial velocity = 0 m/s because it just falls of.


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Re: PHY 101 Projectile motion homework [Re: blackhawk]
    #21507553 -

So for 1 sec it would be: 1/2 (9.8 x 1^2)=4.9?
2 sec= 19.6?

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