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InvisibleHeavyToilet
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Math exam tonight... couple questions...
    #5530068 - 04/18/06 04:08 PM (17 years, 9 months ago)

I got above 90% average in the course so I'm not too concerned... but there are a couple questions I can't figure out.

First one is long division.
(2x^3 - 10x^2 - x - 22) / (2x +1)



After that I'm just stuck and don't know what to do with it.

And finally this question:

The volume of a given mass of has varies directly as the temperature T and inversely as the pressure P. If V=231 cm^3 when T=42 degrees C and P=20(kg/cm^2), what is the volume when T=30 degrees C and P=15(kg/cm^2)

And I just don't understand that one at all.


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InvisibleColonel Kurtz Ph.D
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Re: Math exam tonight... couple questions... [Re: HeavyToilet]
    #5530084 - 04/18/06 04:14 PM (17 years, 9 months ago)

I think the second one is saying that you should go by this formula: V=T/P :shrug:
But I'm not sure at all, so try to test it. That's the best I can do with my level.


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InvisibleHeavyToilet
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Re: Math exam tonight... couple questions... [Re: Colonel Kurtz Ph.D]
    #5530097 - 04/18/06 04:18 PM (17 years, 9 months ago)

if it is V= T/P, then that would mean 42/20 would equal 231. So it can't be that.

And I don't see any other way of relating 42 and 20 to 231.


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Offlinebarfightlard
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Re: Math exam tonight... couple questions... [Re: HeavyToilet]
    #5530107 - 04/18/06 04:22 PM (17 years, 9 months ago)

53?


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"What business is it of yours what I do, read, buy, see, say, think, who I fuck, what I take into my body - as long as I do not harm another human being on this planet?" - Bill Hicks


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Invisibleknowhereman
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Re: Math exam tonight... couple questions... [Re: barfightlard]
    #5530222 - 04/18/06 05:02 PM (17 years, 9 months ago)

ton the 1st problem you have to factor out what you have left up there(-x^2 +4x -22)...uhh use the quadriatic formula.


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Edited by knowhereman (04/18/06 05:04 PM)


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InvisibleHeavyToilet
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Re: Math exam tonight... couple questions... [Re: knowhereman]
    #5530280 - 04/18/06 05:16 PM (17 years, 9 months ago)

Then you'd have -4 +- the root of -72, all over -2.

So basically they'd be imaginary numbers because of the negative in the square root.

I don't understand how this could be applied to the question.


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InvisibleHeavyToilet
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Re: Math exam tonight... couple questions... [Re: HeavyToilet]
    #5530295 - 04/18/06 05:22 PM (17 years, 9 months ago)

Sigh... where's Anno when you need him.


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OfflinefreshlyPLUMP
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Re: Math exam tonight... couple questions... [Re: HeavyToilet]
    #5530318 - 04/18/06 05:27 PM (17 years, 9 months ago)

isnt the quadratic formula like b+- square root of b^2+2ac all over 2a?


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InvisibleHeavyToilet
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Re: Math exam tonight... couple questions... [Re: freshlyPLUMP]
    #5530324 - 04/18/06 05:28 PM (17 years, 9 months ago)

No.

It's -b +- square root of b^2 - 4ac all over 2a.


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OfflineSnaggletooth
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Re: Math exam tonight... couple questions... [Re: HeavyToilet]
    #5530356 - 04/18/06 05:37 PM (17 years, 9 months ago)





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Atheist Chat


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InvisibleHeavyToilet
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Re: Math exam tonight... couple questions... [Re: Snaggletooth]
    #5530376 - 04/18/06 05:44 PM (17 years, 9 months ago)

I got 15 minutes left before I have to leave.

I'm putting my faith in the Pub, come on guys, don't let me down!!

:lol:


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Offlineotr317
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Re: Math exam tonight... couple questions... [Re: HeavyToilet]
    #5530450 - 04/18/06 06:11 PM (17 years, 9 months ago)

ok, for #2 you're forgetting the constant ratio for the gas.

the formula is actually V= RT/P where R is the ratio determined by solving for R, R=VP/T then plugging in your given P,V, and T for the gas.

so if at T=42 degC, V=231 cm^3 and P=20 kg/cm^2

then R= ((20kg/cm^2)x(231cm^3)) / 42C

which equals 4620/42, or 110 (kg x cm)/C

plug in this R for the second set in the form V=RT/P, and you have

V= (110 x 30) / 15 = 220 cm^3

the wierd '(kg x cm)/degC' form that the R value takes allows all the extraneous units of measure to cancel out in solving the equation, leaving you with your desired V units of cm^3 for the given P and T of the problem

note:
sometimes R will be written 'r' or 'k', but it's all the same, in every formula of this type there must be this constant of change


Edited by otr317 (04/18/06 06:14 PM)


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OfflineDocPsilocybin
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Re: Math exam tonight... couple questions... [Re: HeavyToilet]
    #5530494 - 04/18/06 06:26 PM (17 years, 9 months ago)

Still there?

If you are for the first one the final bit you have would be your remainder.

Second question
V1*P1/T1=V2*P2/T2 Fill in the blanks and calculate.

Edit: Whoops (and to above poster, although you could use Universal gas law this is a relationship question and only needs the combined gas law, or even Boyles law (P1*V1=P2*V2), R = 0.08206 isn't needed)


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Edited by DocPsilocybin (04/18/06 06:32 PM)


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Offlineotr317
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Re: Math exam tonight... couple questions... [Re: DocPsilocybin]
    #5530704 - 04/18/06 07:31 PM (17 years, 9 months ago)

Quote:

DocPsilocybin said:
Edit:  Whoops (and to above poster, although you could use Universal gas law this is a relationship question and only needs the combined gas law, or even Boyles law (P1*V1=P2*V2), R = 0.08206 isn't needed)




good point. i tend to use whatever method comes to mind first, it's not always the best one for the job  :grin:


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InvisibleHeavyToilet
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Re: Math exam tonight... couple questions... [Re: otr317]
    #5533070 - 04/19/06 10:23 AM (17 years, 9 months ago)

Hmm, well thanks guys, and we weren't supposed to know any physics formula for the question.

Turns out the test didn't involve either of those questions... except there was a division one but there was no remainder. I also asked a class mate what the deal with the first question was, and he said we were supposed to use fraction coefficients.

Also I ended up doing EXTREMELY well on the exam. I'm sure I must have gotten somewhere around the middle to upper 90s on it since I checked all the answers.


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