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Registered: 01/30/03
Posts: 7
Last seen: 14 years, 4 months
Physics help
    #2200412 - 12/25/03 02:31 AM (14 years, 4 months ago)

Hi, I dont normally post these types of things, but I am having alot of misunderstandings dealing with a few physics problems involving sound waves, and wave properties in general. If someone with some knowledge could lend me a hand, my appreciation would be tremendous :smile:

Ok so here is the problem im having troubles with, as basic as it may be to some, I simply cannot find a reasonable explanation as to the formula to go about it.

Carol drops a stone into a mine shaft 122.5m deep. How soon after she drops the stone does she hear it hit the bottom of the shaft?. I know the speed of sound is 343m/s (at 20degrees), and it would be easy enough just to find out how fast it would travel 122.5m (because of the speed constant at 20degrees). However this is not correct, what im missing has to be the length of time the stone takes to drop to the bottom, added onto the length of time it takes for carol to hear the sound after it has hit.

Does anyone have a method to go about this, im not asking for the answer itself, but maybe a formula, or way to go about it.

If anyone was even just a little stimulated by this basic physics question, and amidst the christmas season, while still full of joy in their hearts, wishes to lend a hand and help me out with further questions, I would be very much appreciated. I just cant seem to grasp this entire unit. (pendulums, simple harmonic motion, waves). I have everything else completed, but this is keeping me stumped, and rather nervous, as my deadline approaches to get everything done (home schooling). Thanks for your time regardless, and merry christmas to everyone :smile:

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Registered: 06/15/02
Posts: 15,608
Re: Physics help [Re: sh1ver]
    #2200501 - 12/25/03 03:35 AM (14 years, 4 months ago)

Dammit!! What the hell is that formula.....???

It is a formula that determines the distance moved of accelerating
objects. It is a simple algebriac formula that you have to punch
in the accelerating force(gravity), the distance, time, etc...
It should be like the first formula you learned in physics class.
Just solve for time and that is how long it took the stone to drop.

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Registered: 05/09/03
Posts: 7,532
Loc: Brick City
Re: Physics help [Re: sh1ver]
    #2200886 - 12/25/03 01:39 PM (14 years, 4 months ago)

x= (g*t^2)/2

122.5 = (9.8*t^2)/2

245 = 9.8*t^2

25 = t^2 so t = sqrt(25)=5

The freefall will take 5 seconds

If the speed of sound is 343 m/s (I'm not looking it up) then 122.5/343= .357s for the sound to come back up -- that is if your teacher really wants you to include this.

Ttl time = 5.357s


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