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extreme


Registered: 04/05/11
Posts: 9,340
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19 runs? Basically the same as disorder said but just subtract one inning, or like move them all up an inning? 0 runs in first AND second, 1 run in third, and 3 runs in 4-9? Is that correct?
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DividedQuantum
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Re: mathematical brain teaser thread [Re: extreme]
#22038407 - 08/03/15 04:51 PM (8 years, 5 months ago) |
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No, that too, is incorrect.
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Sun King



Registered: 02/15/14
Posts: 4,069
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I call shenanigans!
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extreme


Registered: 04/05/11
Posts: 9,340
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Re: mathematical brain teaser thread [Re: Sun King]
#22039662 - 08/03/15 08:34 PM (8 years, 5 months ago) |
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extreme


Registered: 04/05/11
Posts: 9,340
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Re: mathematical brain teaser thread [Re: extreme]
#22039754 - 08/03/15 08:40 PM (8 years, 5 months ago) |
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Wait shit, one more guess, they are the home team so they don't bat in the bottom of nine so subtract another 3 from my last answer = 16... if that's wrong I'll stop trying, sorry for spamming this thread lol. This makes sense though...
Also I feel like this needs to be posted.............. courtesy of http://www.poetryfoundation.org/poem/174665
Quote:
The outlook wasn’t brilliant for the Mudville nine that day; The score stood four to two with but one inning more to play. And then when Cooney died at first, and Barrows did the same, A sickly silence fell upon the patrons of the game.
A straggling few got up to go in deep despair. The rest Clung to that hope which springs eternal in the human breast; They thought if only Casey could but get a whack at that— We’d put up even money now with Casey at the bat.
But Flynn preceded Casey, as did also Jimmy Blake, And the former was a lulu and the latter was a cake; So upon that stricken multitude grim melancholy sat, For there seemed but little chance of Casey’s getting to the bat.
But Flynn let drive a single, to the wonderment of all, And Blake, the much despised, tore the cover off the ball; And when the dust had lifted, and men saw what had occurred, There was Jimmy safe at second and Flynn a-hugging third.
Then from 5,000 throats and more there rose a lusty yell; It rumbled through the valley, it rattled in the dell; It knocked upon the mountain and recoiled upon the flat, For Casey, mighty Casey, was advancing to the bat.
There was ease in Casey’s manner as he stepped into his place; There was pride in Casey’s bearing and a smile on Casey’s face. And when, responding to the cheers, he lightly doffed his hat, No stranger in the crowd could doubt ’twas Casey at the bat.
Ten thousand eyes were on him as he rubbed his hands with dirt; Five thousand tongues applauded when he wiped them on his shirt. Then while the writhing pitcher ground the ball into his hip, Defiance gleamed in Casey’s eye, a sneer curled Casey’s lip.
And now the leather-covered sphere came hurtling through the air, And Casey stood a-watching it in haughty grandeur there. Close by the sturdy batsman the ball unheeded sped— “That ain’t my style,” said Casey. “Strike one,” the umpire said.
From the benches, black with people, there went up a muffled roar, Like the beating of the storm-waves on a stern and distant shore. “Kill him! Kill the umpire!” shouted some one on the stand; And it’s likely they’d have killed him had not Casey raised his hand.
With a smile of Christian charity great Casey’s visage shone; He stilled the rising tumult; he bade the game go on; He signaled to the pitcher, and once more the spheroid flew; But Casey still ignored it, and the umpire said, “Strike two.”
“Fraud!” cried the maddened thousands, and echo answered fraud; But one scornful look from Casey and the audience was awed. They saw his face grow stern and cold, they saw his muscles strain, And they knew that Casey wouldn’t let that ball go by again.
The sneer is gone from Casey’s lip, his teeth are clinched in hate; He pounds with cruel violence his bat upon the plate. And now the pitcher holds the ball, and now he lets it go, And now the air is shattered by the force of Casey’s blow.
Oh, somewhere in this favored land the sun is shining bright; The band is playing somewhere, and somewhere hearts are light, And somewhere men are laughing, and somewhere children shout; But there is no joy in Mudville—mighty Casey has struck out.
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DividedQuantum
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Re: mathematical brain teaser thread [Re: extreme]
#22039822 - 08/03/15 09:01 PM (8 years, 5 months ago) |
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Nah, that's not right either.
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extreme


Registered: 04/05/11
Posts: 9,340
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Damn it I give up then I tried. If you count my reflections on disorder's answer as an actual answer of my own, then I have effectively struck out haha. Baseball is a cool sport for math questions though
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ballsalsa
Universally Loathed and Reviled



Registered: 03/11/15
Posts: 20,852
Loc: Foreign Lands
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Re: mathematical brain teaser thread [Re: extreme]
#22039860 - 08/03/15 09:13 PM (8 years, 5 months ago) |
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Quote:
DividedQuantum said: PROBLEM #25
Quote:
During a baseball game in Mudville, Casey was Mudville's lead-off batter. There were no substitutions or changes in the batting order of the nine Mudville men throughout the nine-inning game. It turned out that Casey came to bat in every inning. What is the least number of runs Mudville could have scored?
In the first inning Casey walks, and so do the next two batters. The next three strike out. In the second inning, the first three walk again, so Casey comes back to the plate, but every runner gets picked off so the inning ends and Casey comes back to bat at the start of the third inning. Rinse and repeat until the game is finished with a score of 0 for mudville
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DividedQuantum
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Re: mathematical brain teaser thread [Re: ballsalsa]
#22039933 - 08/03/15 09:31 PM (8 years, 5 months ago) |
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Quote:
ballsalsa said: In the first inning Casey walks, and so do the next two batters. The next three strike out. In the second inning, the first three walk again, so Casey comes back to the plate, but every runner gets picked off so the inning ends and Casey comes back to bat at the start of the third inning. Rinse and repeat until the game is finished with a score of 0 for mudville
  
Correct!
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DividedQuantum
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PROBLEM #26
Quote:
John F. Kennedy was born in 1917. He became president in 1960. In 1963, his age was 46 and he had been in office 3 years. The sum of four of these numbers (1917, 1960, 46, and 3) is 3,926.
Charles de Gaulle was born in 1890. He became president of France in 1958. In 1963 his age was 73 and he had been in office 5 years. The sum of the four numbers 1890, 1958, 73, and 5 is 3,926.
Can you explain this remarkable coincidence?
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Sun King



Registered: 02/15/14
Posts: 4,069
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Quote:
DividedQuantum said: PROBLEM #26
Quote:
John F. Kennedy was born in 1917. He became president in 1960. In 1963, his age was 46 and he had been in office 3 years. The sum of four of these numbers (1917, 1960, 46, and 3) is 3,926.
Charles de Gaulle was born in 1890. He became president of France in 1958. In 1963 his age was 73 and he had been in office 5 years. The sum of the four numbers 1890, 1958, 73, and 5 is 3,926.
Can you explain this remarkable coincidence?
Try the conspiracy forum, they can explain it or that crazy guy in the pub.
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Sun King



Registered: 02/15/14
Posts: 4,069
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Re: mathematical brain teaser thread [Re: Sun King]
#22053321 - 08/06/15 12:09 PM (8 years, 5 months ago) |
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DisoRDeR
motional



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Re: mathematical brain teaser thread [Re: Sun King]
#22053336 - 08/06/15 12:11 PM (8 years, 5 months ago) |
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I was born in 1982. I graduated from university in 2006. In 1963, my age was -19 and I had been finished school for -43 years. The sum of four of these numbers (1982, 2006, -19, and -43) is 3,926.
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Sun King



Registered: 02/15/14
Posts: 4,069
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Re: mathematical brain teaser thread [Re: DisoRDeR]
#22053368 - 08/06/15 12:18 PM (8 years, 5 months ago) |
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I was born in 1962 and graduated from university in 2014. In 1912 I was -50 years old. That adds up to 3926.
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DividedQuantum
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Re: mathematical brain teaser thread [Re: DisoRDeR]
#22053388 - 08/06/15 12:20 PM (8 years, 5 months ago) |
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Pick a date (e.g. 1963) and call it Date 1. Any earlier date (Date 2) added to the number of years between the two dates will total Date 1. Two such totals will be twice Date 1. So:
1917 + 46 = 1963, and 1960 + 3 = 1963.
1890 + 73 = 1963, and 1958 + 5 = 1963.
1963 x 2 = 3,926
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Sun King



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DividedQuantum
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PROBLEM #27
Quote:
In the United States, at least eight coins are required to make the sum of ninety-nine cents: a half-dollar, a quarter, two dimes, and four pennies. Imagine yourself the leader of a small, newly independent nation. You have the task of setting up a system of coinage based on the cent as the smallest unit. Your objective is to issue the smallest number of different coins that will enable any value from one to one hundred cents (inclusive) to be made with no more than two coins.
For example, the objective is easily met with eighteen coins of the following values: 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 20, 30, 40, 50, 60, 70, 80, 90.
Can you do better? Every value must be obtainable either by one coin or as the sum of two coins. The two coins need not, of course, have different values.
BONUS PROBLEM
Quote:
A boy and a girl are sitting on the front steps of their commune.
"I'm a boy," said the one with black hair.
"I'm a girl, said the one with red hair.
At least one of them is lying. Which is it?
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Sun King



Registered: 02/15/14
Posts: 4,069
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BONUS PROBLEM
Quote:
A boy and a girl are sitting on the front steps of their commune.
"I'm a boy," said the one with black hair.
"I'm a girl, said the one with red hair.
At least one of them is lying. Which is it?
Both are lying. Damn commie liars.
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DividedQuantum
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Re: mathematical brain teaser thread [Re: Sun King]
#22053454 - 08/06/15 12:41 PM (8 years, 5 months ago) |
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Quote:
Sun King said: Both are lying. Damn commie liars.
Correct.
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DividedQuantum
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Registered: 12/06/13
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Quote:
DividedQuantum said: PROBLEM #27
Quote:
In the United States, at least eight coins are required to make the sum of ninety-nine cents: a half-dollar, a quarter, two dimes, and four pennies. Imagine yourself the leader of a small, newly independent nation. You have the task of setting up a system of coinage based on the cent as the smallest unit. Your objective is to issue the smallest number of different coins that will enable any value from one to one hundred cents (inclusive) to be made with no more than two coins.
For example, the objective is easily met with eighteen coins of the following values: 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 20, 30, 40, 50, 60, 70, 80, 90.
Can you do better? Every value must be obtainable either by one coin or as the sum of two coins. The two coins need not, of course, have different values.
Any takers?
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