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OfflineQ.I
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Re: Math paradox, whats the answer? [Re: zappaisgod]
    #21207527 - 01/31/15 04:18 PM (9 years, 1 month ago)

I used to be able to flip a coin and make it come out how I wanted almost every time. It's all in the timing I think.

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InvisibleSoloTrip
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Re: Math paradox, whats the answer? [Re: koods]
    #21207611 - 01/31/15 04:43 PM (9 years, 1 month ago)

I could teach you calculus faster than a commercial break. Do you doubt me? You need not even have passed algebra. This is the graph for x^2.
1*1=1 2*2=4 etc. You only have to be able to see that much.


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Edited by SoloTrip (01/31/15 04:59 PM)

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Offlinekoods
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Re: Math paradox, whats the answer? [Re: zappaisgod]
    #21207671 - 01/31/15 05:01 PM (9 years, 1 month ago)

Quote:

zappaisgod said:
Quote:

psi said:
Quote:

blojo02184 said:
The Fibonacci triangle... Where you guys going with that?



Never heard it referred to as that (I know it as Pascal's triangle) but I think there is some relationship to the Fibonacci sequence. That came up in addressing the question "What are the odds of getting 5 heads and 5 tails in 10 throws?" (in any order.)



Well?  What's the fucking answer?




252/1024


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NotSheekle said
“if I believed she was 16 I would become unattracted to her”

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Offlinekoods
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Re: Math paradox, whats the answer? [Re: SoloTrip]
    #21207873 - 01/31/15 05:46 PM (9 years, 1 month ago)

Quote:

SoloTrip said:
I could teach you calculus faster than a commercial break. Do you doubt me? You need not even have passed algebra. This is the graph for x^2.
1*1=1 2*2=4 etc. You only have to be able to see that much.




That's not calculus, that's geometry.

I got a B- in calculus :crankey:


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NotSheekle said
“if I believed she was 16 I would become unattracted to her”

Edited by koods (01/31/15 05:48 PM)

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InvisibleSoloTrip
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Re: Math paradox, whats the answer? [Re: koods]
    #21208207 - 01/31/15 06:43 PM (9 years, 1 month ago)

Well then this is just review. The graph of y = 2x displays the rate of change, or slope at any point for the graph of y=x^2.



In order to acquire the equation for this second graph it is necessary to take a derivative. Multiply the exponent (in this case 2) by the number in front of x which in the case of (1)x^2 is simply 1. and drop one degree from the exponent which in this case is squared becomes x^1. So taking the derivative of y =  x^2 becomes y = 2x.
Blam! That's the first two weeks of Calculus 1 explained in two minutes.


--------------------

Edited by SoloTrip (01/31/15 06:44 PM)

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InvisibleAcidic_SlothM
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Re: Math paradox, whats the answer? [Re: SoloTrip]
    #21208228 - 01/31/15 06:47 PM (9 years, 1 month ago)

you explained it okay, i guess.


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Offlineblojo02184
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Re: Math paradox, whats the answer? [Re: Acidic_Sloth]
    #21208433 - 01/31/15 07:25 PM (9 years, 1 month ago)

Shit... Let me go get my statistics notebook

Its basically the combination of heads or tails to the 9 degree or something like that.

Give me 20 minutes, I'll have it

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Offlinemorrowasted
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Re: Math paradox, whats the answer? [Re: koods]
    #21208444 - 01/31/15 07:27 PM (9 years, 1 month ago)

Quote:

koods said:
If it landed 99 times on the same side, there is something wrong with the coin :lol:


.

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Offlineblojo02184
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Re: Math paradox, whats the answer? [Re: morrowasted]
    #21208538 - 01/31/15 07:51 PM (9 years, 1 month ago)

So I comes down to the number of combinations of flipping a coin 10 times.

The equation is
10^2

When figuring out the probability of getting 9 heads in a row when selecting 10 flips the equation changes slightly.

N!/(2^10(X!))
Where N is the number of flips being examined, and X being the number of heads.

Which comes out to .009765625
.97% chance of getting 9 tails or heads in a set of ten flips. Almost 1% chance.

The statician is still going to tell you that its a 50/50 chance on the next flip.

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Offlinekoods
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Re: Math paradox, whats the answer? [Re: blojo02184]
    #21208719 - 01/31/15 08:30 PM (9 years, 1 month ago)

Quote:

blojo02184 said:
So I comes down to the number of combinations of flipping a coin 10 times.

The equation is
10^2

When figuring out the probability of getting 9 heads in a row when selecting 10 flips the equation changes slightly.

N!/(2^10(X!))
Where N is the number of flips being examined, and X being the number of heads.

Which comes out to .009765625
.97% chance of getting 9 tails or heads in a set of ten flips. Almost 1% chance.

The statician is still going to tell you that its a 50/50 chance on the next flip.



The chance of getting 9 heads or 9 tails us 10/1024.

Or .976 as you said.


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NotSheekle said
“if I believed she was 16 I would become unattracted to her”

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Offlinekoods
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Re: Math paradox, whats the answer? [Re: koods]
    #21319421 - 02/23/15 07:20 PM (9 years, 1 month ago)

What are the chances of playing Russian roulette five times and not shooting yourself in the head? The individual chance of each attempt is 1/6.


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NotSheekle said
“if I believed she was 16 I would become unattracted to her”

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OfflineEllis Dee
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Re: Math paradox, whats the answer? [Re: koods]
    #21320384 - 02/23/15 10:33 PM (9 years, 1 month ago)

Quote:

koods said:
What are the chances of playing Russian roulette five times and not shooting yourself in the head? The individual chance of each attempt is 1/6.



The odds of discharging a round is 1 in 6.  Five out of six times whoever tries that will have a bullet in the head. Better to do it with the gun pointed in a safe direction. :wink:


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OfflineWaffleBear
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Re: Math paradox, whats the answer? [Re: Ellis Dee]
    #21320567 - 02/23/15 11:16 PM (9 years, 1 month ago)

I use to gamble a lot with bitcoin, mostly 50/50 odds. It's surprising how many times you can lose back to back, my record losing spree is in the 12-16 range. 4-6 consecutive losses feels fairly common if you play enough.
Maybe it's semi-rigged though. Then again maybe not. One day I logged in randomly and won 1/80 on my first bid... first & last bid that day :smile:

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