
subiedude
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another math problem in need of help
#11386334  11/04/09 08:20 PM (8 years, 8 months ago) 


EXPONENTIAL AND LOGARITHMIC FUNCTIONS (INVERSE FUNCTIONS)
a) determine if the function is onetoone b) if the function is onetoone, find a formula for the inverse.
f(x)= (x+5)^3
i know it's onetoone, it's the formula im having trouble with. the cube is throwing me off.

Entropymancer
Registered: 07/16/05
Posts: 10,207

Re: another math problem in need of help [Re: subiedude]
#11386354  11/04/09 08:21 PM (8 years, 8 months ago) 


Howzabout x equals cuberootofy minus 5?

kanglow
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Re: another math problem in need of help [Re: subiedude]
#11386355  11/04/09 08:22 PM (8 years, 8 months ago) 


Quote:
subiedude said: the cube is throwing me off.
then stop eating them before you math
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Neuron
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Re: another math problem in need of help [Re: kanglow]
#11386362  11/04/09 08:23 PM (8 years, 8 months ago) 


MATH LEARNING CENTER


Entropymancer
Registered: 07/16/05
Posts: 10,207

Re: another math problem in need of help [Re: Neuron]
#11386372  11/04/09 08:25 PM (8 years, 8 months ago) 


Quote:
Neuron said: MATH LEARNING CENTER
Blasphemy

subiedude
SUBIE!!!
Registered: 02/06/09
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Re: another math problem in need of help [Re: Entropymancer]
#11386374  11/04/09 08:25 PM (8 years, 8 months ago) 


Quote:
Entropymancer said: Howzabout x equals cuberootofy minus 5?
WINNER

dr_gonz
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Re: another math problem in need of help [Re: subiedude]
#11386396  11/04/09 08:28 PM (8 years, 8 months ago) 


explain steps

Entropymancer
Registered: 07/16/05
Posts: 10,207

Re: another math problem in need of help [Re: subiedude]
#11386400  11/04/09 08:29 PM (8 years, 8 months ago) 


This sort of algebra is really easy to think through.
You know you want to get rid of the exponent around (x+5) so you can get x by itself. So just take each side to the 1/3rd power (which is to say, take the cube root of each side). Then all you have to do is subtract the 5 of both sides, and

Tedwilto
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Re: another math problem in need of help [Re: Entropymancer]
#11386468  11/04/09 08:37 PM (8 years, 8 months ago) 


y=(x+5)^3 cube rootY = x+5 CuberootY  5 = X switch variables:
cuberootX  5 = Y
I think thats the inverse unless im finding something else. who knows,

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pwnasaurus
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Re: another math problem in need of help [Re: Tedwilto]
#11386980  11/04/09 09:38 PM (8 years, 8 months ago) 


Quote:
Tedwilto said: y=(x+5)^3 cube rootY = x+5 CuberootY  5 = X switch variables:
cuberootX  5 = Y
I think thats the inverse unless im finding something else. who knows,
This looks good to me.

