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 Liverwort
Man About Town
Registered: 08/15/10
Posts: 16,735
Loc: United States 
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 Who can rise to the arithmetic challenge? 
#15824579 - 02/17/12 06:16 PM (12 years, 1 month ago) |
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True or false:
(3t2 + 5)(t2 - 7t + 2) + (t3 + 5t)(2t - 7)
is equivalent to
5t4 -
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Salomon
ಠ︵ಠ balance ಠ_ಠ weaver ಠ‿ಠ
Registered: 01/17/09
Posts: 25,128
Loc: America, FUCK YEAH
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Re: Who can rise to the arithmetic challenge? [Re: Liverwort]
#15824593 - 02/17/12 06:20 PM (12 years, 1 month ago) |
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well i have a 50-50 chance here....
true
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EVERYTHING EVENTUALLY BECOMES A DESERT 
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 King Klick
That Guy Everyone Knows
Registered: 11/13/11
Posts: 7,267
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Re: Who can rise to the arithmetic challenge? [Re: Salomon]
#15824601 - 02/17/12 06:22 PM (12 years, 1 month ago) |
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True, obviously
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Your god is dead, and I killed him.
When you’re lost, here I am. Forever with your soul
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G-Cotty
Naturalismo
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Re: Who can rise to the arithmetic challenge? [Re: King Klick]
#15824662 - 02/17/12 06:37 PM (12 years, 1 month ago) |
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Physics challenge!!!!!!!!!!!
A proton (q = 1.6 X 10-19 C, m = 1.67 X 10-27 kg) moving with constant velocity enters a region containing a constant magnetic field that is directed along the z-axis at (x.,y) = (0,0) as shown. The magnetic field extends for a distance D = 0.43 m in the x-direction. The proton leaves the field having a velocity vector (vx, vy) = (4 X 105 m/s, 2.1 X 105 m/s).
What is R, the radius of curvature of the motion of the proton while it is in the region containing the magnetic field?
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RonaldFuckingPaul
Our Dear Leader
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Re: Who can rise to the arithmetic challenge? [Re: Salomon]
#15824700 - 02/17/12 06:44 PM (12 years, 1 month ago) |
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Quote:
Salomon said:
well i have a 50-50 chance here....
true
I say false.
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Bodhi of Ankou
*alternate opinion blocks path*
Registered: 06/02/09
Posts: 24,778
Loc: Soviet Canukistan 
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I say potato
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Liverwort
Man About Town
Registered: 08/15/10
Posts: 16,735
Loc: United States
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Re: Who can rise to the arithmetic challenge? [Re: G-Cotty]
#15824707 - 02/17/12 06:45 PM (12 years, 1 month ago) |
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Haha sorry i was gonna post this, but then I figured out how to punch it into wolframalpha.com .
I never finished typing it out here and it somehow published the incomplete post. I'll finish it up for kicks, if anyone wants to try the challenge, but I'm gonna rephrase it.
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qbe
New but old
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Re: Who can rise to the arithmetic challenge? [Re: G-Cotty]
#15824715 - 02/17/12 06:47 PM (12 years, 1 month ago) |
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5*t^4-28*t^3+21*t^2-70*t+10
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I eat mushrooms to meet hippie chicks.
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Liverwort
Man About Town
Registered: 08/15/10
Posts: 16,735
Loc: United States
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Re: Who can rise to the arithmetic challenge? [Re: Liverwort]
#15824722 - 02/17/12 06:48 PM (12 years, 1 month ago) |
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Here is the modified arithmetic challenge:
(3t2 + 5)(t2 - 7t + 2) + (t3 + 5t)(2t - 7)
What you have to do is rephrase it so there are no parenthesis. In other words, put it in completely seperated terms that are being added to (or subtracted from) each other.
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Liverwort
Man About Town
Registered: 08/15/10
Posts: 16,735
Loc: United States
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Re: Who can rise to the arithmetic challenge? [Re: Liverwort]
#15824730 - 02/17/12 06:50 PM (12 years, 1 month ago) |
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Hell yeah, you got it before I could even finish rephrasing it! Hats off to you, qbe. You are a skilled arithmetician!
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Meteloides
Clinically Expressed
Registered: 09/26/11
Posts: 2,187
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Re: Who can rise to the arithmetic challenge? [Re: Liverwort]
#15824759 - 02/17/12 06:56 PM (12 years, 1 month ago) |
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(3t2 + 5)(t2 - 7t + 2) + (t3 + 5t)(2t - 7)
=/=
5t4
False.
I think I did it right but I am way too lazy to actually go through the steps here. 
EDIT:
Dammit, someone beat me to it while I was figuring it out. 
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Edited by Meteloides (02/17/12 06:56 PM)
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DieCommie
Registered: 12/11/03
Posts: 29,258
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Re: Who can rise to the arithmetic challenge? [Re: Liverwort]
#15824774 - 02/17/12 07:00 PM (12 years, 1 month ago) |
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Quote:
zappateer said:
True or false:
(3t2 + 5)(t2 - 7t + 2) + (t3 + 5t)(2t - 7)
is equivalent to
5t4 -
The quickest way to see that its false, without doing any arithmetic at all, is to note that 'answer' is only t to the fourth power. In the expression you have terms of many powers, thus they are not equivalent.
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Liverwort
Man About Town
Registered: 08/15/10
Posts: 16,735
Loc: United States
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Re: Who can rise to the arithmetic challenge? [Re: Meteloides]
#15824780 - 02/17/12 07:01 PM (12 years, 1 month ago) |
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Yeah, qbe's pretty good. But I had to rephrase it anyway, so it was no longer a true/false question. Maybe I'll post another challenge in the future.. haha
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qbe
New but old
Registered: 08/16/11
Posts: 1,253
Loc: Philadelphia
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Re: Who can rise to the arithmetic challenge? [Re: Liverwort]
#15824801 - 02/17/12 07:06 PM (12 years, 1 month ago) |
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Haha, bring it on. Helping people with homework/challenges on the shroomery is my way of studying for college.
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I eat mushrooms to meet hippie chicks.
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Liverwort
Man About Town
Registered: 08/15/10
Posts: 16,735
Loc: United States
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Re: Who can rise to the arithmetic challenge? [Re: qbe]
#15824817 - 02/17/12 07:09 PM (12 years, 1 month ago) |
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What do you study dude?
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qbe
New but old
Registered: 08/16/11
Posts: 1,253
Loc: Philadelphia
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Re: Who can rise to the arithmetic challenge? [Re: Liverwort]
#15824850 - 02/17/12 07:17 PM (12 years, 1 month ago) |
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Bio-mechanical and Human performance engineering. How about you man?
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I eat mushrooms to meet hippie chicks.
Edited by qbe (02/17/12 07:18 PM)
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Liverwort
Man About Town
Registered: 08/15/10
Posts: 16,735
Loc: United States
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Re: Who can rise to the arithmetic challenge? [Re: qbe]
#15824906 - 02/17/12 07:28 PM (12 years, 1 month ago) |
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Wow, that sounds really interesting. I'm an undergrad studying biology.
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qbe
New but old
Registered: 08/16/11
Posts: 1,253
Loc: Philadelphia
Last seen: 1 year, 3 months
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Re: Who can rise to the arithmetic challenge? [Re: Liverwort]
#15824918 - 02/17/12 07:31 PM (12 years, 1 month ago) |
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So you're along the same lines as me. I'm an undergrad also, it's kinda like human biology and mechanical engineering smashed together.
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I eat mushrooms to meet hippie chicks.
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Salomon
ಠ︵ಠ balance ಠ_ಠ weaver ಠ‿ಠ
Registered: 01/17/09
Posts: 25,128
Loc: America, FUCK YEAH
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Re: Who can rise to the arithmetic challenge? [Re: qbe]
#15824938 - 02/17/12 07:35 PM (12 years, 1 month ago) |
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Quote:
qbe said:
Bio-mechanical and Human performance engineering. How about you man?
can you make me one of those human exo-skeletons so i can throw cars and stuff?
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EVERYTHING EVENTUALLY BECOMES A DESERT
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pmb
12121212
Registered: 08/11/08
Posts: 2,567
Loc: Washington
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Re: Who can rise to the arithmetic challenge? [Re: Liverwort]
#15824939 - 02/17/12 07:35 PM (12 years, 1 month ago) |
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Could you plug any number in for t and solve?
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Don't smell the flowers, They're an evil drug to make you lose your mind
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