#include <iostream>
using namespace std;

void print_even(int start, int end)
{
    if(start < end)
    {
        for(int i=start; i<=end; ++i) // count up
        {
            // This is a binary/math trick which will check if
            // the last bit of the integer is 1, if the last bit is 1 the number
            // is odd, therefor it inverses it with '!'
            if( !(i & 1) )
            {
                cout << i << endl;
            }
        }
    }
    else
    {
        for(int i=start; i>=end; --i)
        {
            // This is another math trick that will divide the number with 2 if a
            // fraction remains it will return 1, therefore we are also 
            // inverting this with "!"
            if( !(i % 2 ) )
                cout << i << endl;
        }
    }

    return;
}
int main()
{
    int value1, value2;
    cout << "Please enter a small number." << endl;
    cin >> value1;
    cout << "Please enter a larger number." << endl;
    cin >> value2;

    print_even(value1,value2);
    cout << endl;
    cout << "WOW This program counts by two's very fast!!!!!" << endl;
    cout << endl;
return 0;
}

#include <iostream>
using namespace std;

int main()
{
cout << "This caclualtor only adds positive odd valued numbers. " << endl;
cout << endl;
cout << "Please enter an odd valued interger to add or press 0 (zero) to exit. " << endl;
cout << endl;

int total = 0;

for(int number = 0; ;number++) // infinito for loop that can only be closed by entering zero
{
cin >> number;

if(number <= 0) // break dance
break;
if(number == 7) // skippy 
continue;
if (!(number % 2 == 0)) // THIS PART SEEMS MESSED UP //
cout << "The current total is " << endl;
cout << endl;
total = total + number; 
cout << total << endl;
}
return 0;
}

if (!(number % 2 == 0)) // THIS PART SEEMS MESSED UP //
  cout << "The current total is " << endl;
cout << endl;
total = total + number; 
cout << total << endl;

if (!(number % 2 == 0)) // THIS PART SEEMS MESSED UP //
  cout << "The current total is " << endl;
  cout << endl;
  total = total + number; 
  cout << total << endl;

if (!(number % 2 == 0)) // THIS PART SEEMS MESSED UP //
{
  cout << "The current total is " << endl;
}
cout << endl;
total = total + number; 
cout << total << endl;

Write a program that takes an array of float (with special attention to functions with array parameters) 
and prints its contents to the nearest integer. 
The rounding should be totally programmed by you (don't use any C++ special libraries for this).

You could write two functions in addition to main:

int round (float x)

which would round any float to the nearest int, and return the int value

and

void print_integers(float a [ ], int size)

which would print the contents of array of size size a already rounded to the nearest int.

Your main function could call print_integers, and print_integers would call round for every element of the array, and print the rounded value.

There are several easy ways to make round work. Use any you want, but you will have to write it yourselves.

int round(float x) { return static_cast<int>((x>0.0f) ? x+0.5f : x-0.5f); }
void print_integers(float a[], int size) { for(int i=0; i<size; ++i) std::cout << round(a[i]) << std::endl; }

void print_integers(float a[], int size) 
{
  for(int i=0; i<size; ++i)
    std::cout << std::fixed << std::setprecision(0) << a[i] << std::endl; 
}

#include <iostream>
#include <cstdlib>

using namespace std;

int main()
{
    int numb[3];
    int i, j;

    for(i=0;i<=2;i++)
    {
        cout << "Please enter a integer : ";
        cin >> numb[i];
    }

    for(i=0;i<=2;i++)
    {
        for(j=i+1;j<=2;j++)
        {
          int temp;

          if(numb[i] > numb[j])
          {
              temp = numb[i];
              numb[i] = numb[j];
              numb[j] = temp;
          }
        }
    }

    for(i=0;i<=2;i++)
    {
        cout << endl << numb[i] << endl;
        cout << endl;
    }

    system("pause");
}

#include <iostream>
#include <cstdlib>

using namespace std;

int main()
{
    float numb[3];
    float i;
    int size;

    for(i=0;i<=2;i++)
    {
        cout << "Please enter a integer : ";
        cin >> numb[i];
    }

int round(float x)
return static_cast<int>((x>0.0f) ? x+0.5f : x-0.5f);
void print_integers(float a[], int size){
for(int i=0; i<size; ++i)
    cout << round(a[i]) << endl;
}
    system("pause");
}